What is the possible blood group of children whose parents are heterozygous for A & B blood groups ?
- A, B only
- A, B, AB & O
- AB only
- A, B & AB only
The Correct Option is B
Approach Solution - 1
We are asked to find the possible blood groups (phenotypes) of children when both parents are heterozygous for A and B blood groups respectively.
1. Determine the genotypes of the parents:
- Parent 1 is heterozygous for A blood group. The genotype is IAIO (or IAi).
- Parent 2 is heterozygous for B blood group. The genotype is IBIO (or IBi).
The alleles involved are IA, IB, and IO (or i). IA and IB are codominant, and both are dominant over IO.
2. Determine the possible gametes produced by each parent:
- Parent 1 (IAIO) can produce gametes containing either the IA allele or the IO allele.
- Parent 2 (IBIO) can produce gametes containing either the IB allele or the IO allele.
3. Use a Punnett square to find the possible genotypes of the children:
| Parent 2 (IBIO) Gametes | ||
| Parent 1 (IAIO) Gametes | IB | IO |
| IA | IAIB | IAIO |
| IO | IBIO | IOIO |
4. Determine the phenotype (blood group) for each possible genotype:
- IAIB → Blood group AB
- IAIO → Blood group A
- IBIO → Blood group B
- IOIO → Blood group O
5. List all possible blood groups (phenotypes) of the children:
The children can have blood groups A, B, AB, and O.
Comparing this result with the given options:
- A, B only
- A, B, AB & O
- AB only
- A, B & AB only
The correct option is A, B, AB & O.
Approach Solution -2
When both parents are heterozygous for blood groups A and B, their genotypes are IAi (blood group A) and IBi (blood group B), respectively. The possible combinations of alleles from these parents can be determined using a Punnett square:
| IA (Father) | i (Father) | |
|---|---|---|
| IB (Mother) | IAIB (AB) | IBi (B) |
| i (Mother) | IAi (A) | ii (O) |
Possible Genotypes and Corresponding Blood Groups:
- IAIB: Blood group AB
- IBi: Blood group B
- IAi: Blood group A
- ii: Blood group O
The correct answer is (B) : A, B, AB & O.
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