We need to determine the nature of the roots of the quadratic equation \( \frac{4}{3}x^2 - 2x + \frac{3}{4} = 0 \). The nature of the roots depends on the discriminant \( \Delta \), given by:
\[
\Delta = b^2 - 4ac.
\]
For the equation \( \frac{4}{3}x^2 - 2x + \frac{3}{4} = 0 \), we have \( a = \frac{4}{3} \), \( b = -2 \), and \( c = \frac{3}{4} \). The discriminant is:
\[
\Delta = (-2)^2 - 4 \times \frac{4}{3} \times \frac{3}{4} = 4 - 4 = 0.
\]
Since the discriminant is zero, the roots are real and equal.
Thus, the roots are \( \boxed{\text{Real and equal}} \).