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what is the nature of roots of the quadratic equat
Question:
What is the nature of roots of the quadratic equation \( 6x^2 - 3x + 5 = 0 \)?
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If \( D>0 \), roots are real and unequal. If \( D = 0 \), roots are real and equal. If \( D<0 \), roots are not real.
Bihar Board X - 2024
Bihar Board X
Updated On:
Oct 27, 2025
Real and unequal
Real and equal
Not real
None of these
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The Correct Option is
C
Solution and Explanation
The nature of roots is determined using the discriminant: \[ D = b^2 - 4ac \] For \( 6x^2 - 3x + 5 = 0 \):
\[ D = (-3)^2 - 4(6)(5) = 9 - 120 = -111 \] Since \( D<0 \), the roots are not real.
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