Question

What is the major product formed by HI reaction with

• A. A
• B. B
• C. C
• D. D

Hint:

In Markovnikov addition, the hydrogen atom attaches to the carbon with more hydrogen atoms, and the halide attaches to the carbon with fewer hydrogen atoms (the more substituted carbon).

Answer 1

The Correct Option is A

Step 1: This is an electrophilic addition reaction following Markovnikov's rule.
Step 2: The $H^+$ from HI attacks the double bond to form the most stable carbocation.
Step 3: Attacking the $CH$ carbon creates a tertiary carbocation at the $C(CH_3)$ position, which is more stable than a secondary carbocation.
Step 4: The nucleophile $I^-$ then attacks the tertiary carbocation, resulting in 2-iodo-2-methylbutane. *Note: Based on the options provided, (A) is the closest structural representation of the Markovnikov addition product.*