



To determine the major product formed by the reaction of HI with the given compound, we need to understand the mechanism of reaction with HI (hydrogen iodide).
Hydrogen iodide (HI) is a strong acid that can cleave ether linkages through a nucleophilic substitution reaction. The reaction proceeds with the attack of the iodide ion (I-) on the carbon atom adjacent to the oxygen, followed by the breakdown of the C-O bond.
Let us analyze the possible product formation:
Now, let's examine the provided images and options. One of the given structures is an ether, and our goal is to identify which option forms the major product after the HI reaction:
An ether chain will break to form an alcohol and an alkyl iodide. Considering the most stable carbocation intermediate and the provided images, the reaction involves cleavage favoring the most substituted carbon, leading us to the correct product.
The major product from this reaction is the one depicted in the following option:
This product forms because the iodide ion attacks the more accessible and stable carbon, leading to the corresponding alkyl iodide after the ether is cleaved.

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
The reactions which cannot be applied to prepare an alkene by elimination, are
Choose the correct answer from the options given below:
Choose the correct set of reagents for the following conversion trans $\left( Ph - CH = CH - CH _3\right) \rightarrow \operatorname{cis}\left( Ph - CH = CH - CH _3\right)$

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
Read More: Unsaturated Hydrocarbon