What is the conjugate base of \( OH^- \)?
Show Hint
- \( H_2O \)
- \( O^{2-} \)
- \( H_3O^+ \)
- \( H^+ \)
The Correct Option is B
Solution and Explanation
Understanding Conjugate Acids and Bases: In Brønsted-Lowry acid-base theory, a conjugate base is formed by the removal of a proton (H$^+$) from an acid. Since \({OH}^-\) is itself a base, we need to determine what would form if it were to lose a proton.
Step 1: Analyze the Possibility of OH$^-$ Losing a Proton. OH$^-$ losing a proton (which it doesn't possess in excess) would theoretically produce \({O}^{2-}\).
Step 2: Correct Misconception. However, \( OH^- \) is typically the conjugate base of \( H_2O \). When \( H_2O \) acts as an acid and donates a proton, \( OH^- \) is what remains. Therefore, asking for the conjugate base of \( OH^- \) might seem unconventional, as \( OH^- \) is already a base. But in this context, further loss of a proton would indeed lead to \( O^{2-} \), though this is a highly theoretical and not commonly observed scenario.
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