Question:

What is the characteristic pattern seen in Brown-Sequard syndrome?

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Spinothalamic crosses early, so pain and temperature loss is on the opposite side.
Updated On: Jun 23, 2026
  • Contralateral loss of joint sense and position
  • Contralateral loss of pain
  • Ipsilateral loss of complete sensory functions
  • Contralateral motor functions
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The Correct Option is B

Solution and Explanation

Step 1: Brown-Sequard syndrome results from hemisection (transection of one half) of the spinal cord. The clinical picture follows the level at which each tract crosses the midline. Step 2: The corticospinal (motor) tract and the dorsal columns (fine touch, vibration, joint position sense) cross high up, so a hemisection causes IPSILATERAL motor loss and ipsilateral loss of proprioception and vibration below the lesion. Step 3: The spinothalamic tract carries pain and temperature and crosses within one to two segments of entering the cord. Therefore a hemisection causes CONTRALATERAL loss of pain and temperature, beginning a few segments below the lesion. Step 4: Checking the options against this, contralateral loss of pain (option b) is the correct characteristic feature. Options (a) and (d) wrongly place proprioception and motor loss on the opposite side, and (c) wrongly claims complete sensory loss on one side.
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