Question:

What is the \(10\)'s complement of \((47)_{10}\)?

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10's complement of an n-digit number N is \(10^n-N\).
Updated On: Jul 20, 2026
  • 52
  • 53
  • 54
  • 55
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The Correct Option is B

Solution and Explanation

Step 1: Recall the definition of the 10's complement.
For an $n$-digit decimal number $N$, the $10$'s complement is defined as \[ 10^n-N \] It is used in digital systems to carry out subtraction using addition.

Step 2: Find n for the given number.
$47$ has $2$ digits, so $n=2$ and $10^n=100$.

Step 3: Compute the 10's complement.
\[ 100-47=53 \]

Step 4: Check the other options.
$52$ is the $9$'s complement of $47$, found from $99-47=52$, not the $10$'s complement. $54$ and $55$ would come from an arithmetic slip such as adding an extra $1$ or $2$ after the subtraction.

Step 5: Final conclusion.
\[ \boxed{53} \]
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