Question:
What are \(X\) and \(Y\) respectively in the following reactions?
\[
X+D_2O\rightarrow C_2D_2+P
\]
\[
Y+D_2O\rightarrow CD_4+Q
\]
What are \(X\) and \(Y\) respectively in the following reactions?
\[ X+D_2O\rightarrow C_2D_2+P \] \[ Y+D_2O\rightarrow CD_4+Q \]
\[ X+D_2O\rightarrow C_2D_2+P \] \[ Y+D_2O\rightarrow CD_4+Q \]
Show Hint
\(\mathrm{CaC_2}\) gives acetylene, while \(\mathrm{Al_4C_3}\) gives methane on reaction with water or heavy water.
Updated On: Jun 15, 2026
- \(\mathrm{AlCl_3,\ CaCl_2}\)
- \(\mathrm{Be_2C,\ Al_4C_3}\)
- \(\mathrm{Al_4C_3,\ CaC_2}\)
- \(\mathrm{CaC_2,\ Al_4C_3}\)
Show Solution
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The Correct Option is D
Solution and Explanation
Step 1: Identify \(X\).
Calcium carbide reacts with heavy water \(\mathrm{D_2O}\) to form deuterated acetylene \(\mathrm{C_2D_2}\).
\[ \mathrm{CaC_2+2D_2O\rightarrow C_2D_2+Ca(OD)_2} \]
Therefore,
\[ X=\mathrm{CaC_2} \]
Step 2: Identify \(Y\).
Aluminium carbide reacts with heavy water \(\mathrm{D_2O}\) to form deuterated methane \(\mathrm{CD_4}\).
\[ \mathrm{Al_4C_3+12D_2O\rightarrow 3CD_4+4Al(OD)_3} \]
Therefore,
\[ Y=\mathrm{Al_4C_3} \]
Step 3: Final conclusion.
Hence,
\[ \boxed{X=\mathrm{CaC_2},\quad Y=\mathrm{Al_4C_3}} \]
Calcium carbide reacts with heavy water \(\mathrm{D_2O}\) to form deuterated acetylene \(\mathrm{C_2D_2}\).
\[ \mathrm{CaC_2+2D_2O\rightarrow C_2D_2+Ca(OD)_2} \]
Therefore,
\[ X=\mathrm{CaC_2} \]
Step 2: Identify \(Y\).
Aluminium carbide reacts with heavy water \(\mathrm{D_2O}\) to form deuterated methane \(\mathrm{CD_4}\).
\[ \mathrm{Al_4C_3+12D_2O\rightarrow 3CD_4+4Al(OD)_3} \]
Therefore,
\[ Y=\mathrm{Al_4C_3} \]
Step 3: Final conclusion.
Hence,
\[ \boxed{X=\mathrm{CaC_2},\quad Y=\mathrm{Al_4C_3}} \]
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