What are X and Y respectively in the following reactions?
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In electrophilic aromatic substitution reactions involving amides and related groups, pyridine can help direct the incoming electrophile to specific positions on the ring.
The reaction shows the halogenation of an amide group (\(\text{NHCOCH}_3\)) with bromine. Pyridine is a mild base and it directs the substitution at the position ortho to the existing \(\text{NHCOCH}_3\) group. The reaction produces an intermediate compound \(\text{NHCOCH}_3, \text{NH}_2\).
In the second step, bromine further reacts with the intermediate to give the final product.
Thus, the correct answer is \( \text{NHCOCH}_3, \text{NH}_2 \).
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