Using Darcy’s law:
\[
Q = k \, A \, \frac{h}{L}
\]
Given:
\[
Q = 100\ \text{mm}^3/\text{min},\quad
A = 4000\ \text{mm}^2,\quad
h = 600\ \text{mm},\quad
L = 300\ \text{mm}.
\]
Substitute:
\[
100 = k \times 4000 \times \frac{600}{300}
\]
\[
100 = k \times 4000 \times 2 = 8000k
\]
\[
k = \frac{100}{8000} = 0.0125\ \text{mm/min}
\]
Rounded to three decimal places:
\[
\boxed{0.013\ \text{mm/min}}
\]