(a) Given: a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
a = 12, b = -4, c = 2
Putting the given values in L.H.S. = 12 ÷ (-4 + 2) = 12 ÷ (-2) = 12 ÷ (\(-\frac{1}{2}\)) = \(-\frac{12}{2}\) = -6
Putting the given values in R.H.S. = [12 ÷ (-4)] + (12 ÷ 2) = (12 × \(-\frac{1}{4}\)) + 6 = -3 + 6 = 3
Since L.H.S. ≠ R.H.S.
Hence, verified.
(b) Given: a ÷ (b + c) ≠ (a ÷ b) + (a ÷ c)
a = - 10, b = 1, c = 1
Putting the given values in L.H.S. = -10 ÷ (1 + 1) = - 10 ÷ (2) = -5
Putting the given values in R.H.S. = [-10 ÷ 1] + (-10 ÷ 1) = -10 - 10 = -20
Since, L.H.S. ≠ R.H.S.
Hence, verified.


| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |







| So No | Base | Height | Area of parallelogram |
|---|---|---|---|
| a. | 20 cm | - | 246 \(cm^2\) |
| b. | - | 15 cm | 154.5 \(cm^2\) |
| c. | - | 8.4 cm | 48.72 \(cm^2\) |
| d. | 15.6 cm | - | 16.38 \(cm^2\) |
| Base | Height | Area of triangle |
|---|---|---|
| 15 cm | - | 87 \(cm^2\) |
| - | 31.4 mm | 1256 \(mm^2\) |
| 22 cm | - | 170.5 \(cm^2\) |
