(i) To show: \(A ∪ (A ∩ B) = A \)
We know that
\(A ⊂ A \)
\(A ∩ B ⊂ A \)
\(∴ A ∪ (A ∩ B) ⊂ A … (1) \)
Also, \(A ⊂ A ∪ (A ∩ B) … (2) \)
∴ From (1) and (2) ,\( A ∪ (A ∩ B) = A \)
(ii) To show: \(A ∩ (A ∪ B) = A\)
\(A ∩ (A ∪ B) = (A ∩ A) ∪ (A ∩ B) \)
\(= A ∪ (A ∩ B)\)
\(= A\) {from (1)}
\(f(x) = \begin{cases} x^2, & \quad 0≤x≤3\\ 3x, & \quad 3≤x≤10 \end{cases}\)
The relation g is defined by
\(g(x) = \begin{cases} x^2, & \quad 0≤x≤2\\ 3x, & \quad 2≤x≤10 \end{cases}\)
Show that f is a function and g is not a function.
Some important operations on sets include union, intersection, difference, and the complement of a set, a brief explanation of operations on sets is as follows:
1. Union of Sets:
2. Intersection of Sets:
3.Set Difference:
4.Set Complement: