Question

Upon increase in pressure for dissociation of $N_{2}O_{4}$ into $NO_{2}$ equilibrium shift towards ________.

• A. forward direction
• B. backward direction
• C. no change
• D. first in forward direction then in backward direction

Hint:

High Pressure $\rightarrow$ Shift to fewer gas moles.

Answer 1

The Correct Option is B

Step 1: Concept
Le Chatelier’s Principle regarding pressure.
Step 2: Analysis
Reaction: $N_2O_4 (g) \rightleftharpoons 2NO_2 (g)$. - Moles on Reactant side = 1 - Moles on Product side = 2
Step 3: Effect of Pressure
Increasing pressure shifts the equilibrium towards the side with fewer moles of gas to counteract the change.
Step 4: Conclusion
Since the reactant side ($N_2O_4$) has fewer moles, the equilibrium shifts in the backward direction.
Final Answer:(B)