Let the number of units of P and Q sold be \( x \) and \( y \), respectively. Since the products are sold in the ratio 10:1, we have the relationship:
\[
\frac{x}{y} = 10 → x = 10y
\]
Let \( y \) be the number of units of Q sold.
- The revenue from selling \( x \) units of P and \( y \) units of Q is:
\[
R = 10x + 40y = 10(10y) + 40y = 140y
\]
- The total variable cost for selling \( x \) units of P and \( y \) units of Q is:
\[
VC = 5x + 20y = 5(10y) + 20y = 70y
\]
- The total cost (fixed + variable) is:
\[
C = 1,40,000 + 70y
\]
At the break-even point, revenue equals cost:
\[
R = C
\]
\[
140y = 1,40,000 + 70y
\]
\[
70y = 1,40,000 → y = \frac{1,40,000}{70} = 2000
\]
Thus, \( x = 10y = 20,000 \). The total revenue is:
\[
R = 140y = 140 \times 2000 = 2,80,000
\]