Question:

Two moles of an ideal gas at 1 bar pressure and 298 K is expanded into vacuum to double the volume. The work done is:

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In free expansion (expansion into vacuum), \( P_{\text{ext}}=0 \), so work done is always zero irrespective of volume change.
Updated On: May 6, 2026
  • \( 2 \, \text{J} \)
  • \( 0 \, \text{J} \)
  • \( 1.5 \, \text{J} \)
  • \( 10 \, \text{J} \)
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The Correct Option is B

Solution and Explanation

Step 1: Identify the process.
The gas expands into vacuum, which is called free expansion.

Step 2: Write work formula.

\[ W = -\int P_{\text{ext}}\, dV \]

Step 3: Determine external pressure.

In vacuum, external pressure is zero:
\[ P_{\text{ext}} = 0 \]

Step 4: Substitute in work formula.

\[ W = -\int 0 \cdot dV \]
\[ W = 0 \]

Step 5: Physical interpretation.

Since there is no external resistance, the gas does no work during expansion.

Step 6: Important concept.

Work depends on external pressure, not internal pressure.

Step 7: Final conclusion.

\[ \boxed{0 \, \text{J}} \]
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