To find the probability that the first drawn marble is red and the second drawn marble is white, with replacement after each drawing, we start by understanding the probability formulas involved:
Therefore, the probability that the first drawn marble is red and the second drawn marble is white is \(\frac{4}{75}\).
The correct answer is: \(\frac{4}{75}\).
The total number of marbles in the box is:
$10 + 30 + 20 + 15 = 75$
The probability of drawing a red marble first is:
$\frac{10}{75}$
Since replacement is made, the probability of drawing a white marble next is:
$\frac{30}{75}$
Therefore, the combined probability of first drawing a red marble and then a white marble is:
$\frac{10}{75} \times \frac{30}{75} = \frac{4}{75}$
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]