Step 1: Find speed of light in the medium.
\[
v = \frac{\text{distance}}{\text{time}} = \frac{3 \, \text{cm}}{0.2 \, \text{ns}}
\]
\[
v = \frac{3 \times 10^{-2}}{0.2 \times 10^{-9}} = 1.5 \times 10^8 \, \text{m/s}
\]
Step 2: Calculate refractive index of the medium.
\[
n = \frac{c}{v} = \frac{3 \times 10^8}{1.5 \times 10^8} = 2
\]
Step 3: Find critical angle.
\[
\sin c = \frac{1}{n} = \frac{1}{2}
\]
\[
c = 30^\circ
\]
Step 4: Compare angle of incidence for ray A.
Ray A has angle \(15^\circ\), which is less than critical angle.
\[
15^\circ<30^\circ
\]
So, no total internal reflection for ray A.
Step 5: Compare angle of incidence for ray B.
Ray B has angle \(42^\circ\), which is greater than critical angle.
\[
42^\circ>30^\circ
\]
So, total internal reflection occurs for ray B.
Only ray B undergoes total internal reflection.
Step 6: Final conclusion.
\[
\boxed{\text{Option (C)}}
\]