Total possible outcomes when two dice are rolled:
\[
6 \times 6 = 36.
\]
Favorable outcomes for sum \(>9 \):
\[
(4,6), (5,5), (5,6), (6,4), (6,5), (6,6).
\]
Total favorable outcomes = 6.
Probability:
\[
P(E) = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{6}{36} = \frac{1}{6}.
\]