Two atoms are bonding along the Z-axis. How will the \( \pi^* \) orbital look like (Z is the internuclear axis)?
Two atoms are bonding along the Z-axis. How will the \( \pi^* \) orbital look like (Z is the internuclear axis)?
- A
- B
- C
- D
The Correct Option is C
Solution and Explanation
In the case of two atoms bonding along the Z-axis, their \(\pi^*\) orbital forms as a result of the interaction between the atomic orbitals. The \(\pi^*\) orbital is the anti-bonding molecular orbital, which has a node along the internuclear axis (Z-axis). Step 2: Analyzing the given options.
- Option 1: Incorrect. This shows a bonding orbital, not the anti-bonding orbital (\(\pi^*\)).
- Option 2: Incorrect. This is another incorrect representation, showing a symmetric interaction that does not align with the anti-bonding nature.
- Option 3: Correct. This is the anti-bonding \(\pi^*\) orbital, which has a nodal plane along the internuclear axis (Z-axis).
- Option 4: Incorrect. This representation is not accurate for a \(\pi^*\) orbital.
Step 3: Conclusion.
The correct option is (C) because the anti-bonding \(\pi^*\) orbital has a nodal plane along the Z-axis, as shown in the diagram for Option 3. Option 3.
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