The magnetic moment (\( \mu \)) is related to the number of unpaired electrons (\( n \)) by the formula :
\( \mu = \sqrt{n(n+2)} \, \text{BM} \)
\( \mu = 6.06 \, \text{BM} \)
\( 6.06 = \sqrt{n(n+2)} \)
Squaring both sides :
\( 36.72 = n(n+2) \)
\( n \approx 5 \) (nearest integer).
Since Mn has 5 unpaired electrons, its oxidation state must be +2, as follows :
\( \text{Mn}^{2+} \Rightarrow x = +2. \)
The number of unpaired electrons is 5, and the oxidation state of Mn is +2.
So, Mn must be in +2 oxidation state (Mn+2)
\(⇒ 2 + (–6) = –x \)
\(⇒ –4 = –x \)
\(⇒ x = 4\)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.
A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.
A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.