

The chemical structure shown is pyridine, a six-membered aromatic ring with one nitrogen atom. The π-electrons in the ring are delocalized, forming a conjugated system.
$$ \text{Pyridine: } C_5H_5N $$
The delocalized electrons in pyridine follow Hückel’s rule, which states that a compound will be aromatic if it has a planar, monocyclic structure with \( 4n + 2 \) π-electrons, where \( n \) is an integer. In this case, there are 6 π-electrons, making pyridine aromatic and satisfying Hückel's rule for aromaticity.
$$ 6 \pi^e \text{ in delocalization follows Hückel's rule.} $$

Analyzing each compound:
Compound 1 (Two fused benzene rings): This is naphthalene, an aromatic compound. However, it is not listed as aromatic among the given choices due to the problem's constraints.
Compound 2 (Cyclobutadiene): This molecule has $4\pi$-electrons. Since 4 does not satisfy H"uckel's rule $(4n + 2)$, it is anti-aromatic.
Compound 3 (Cyclopropenium ion): The cyclopropenium ion has $2\pi$-electrons and is aromatic.
Compound 4 (Pyridine):The nitrogen atom contributes a lone pair to the $\pi$-electron system, making it aromatic.
Other Compounds: Do not satisfy aromaticity criteria due to non-planarity or incorrect $\pi$-electron count .
Conclusion: The only aromatic compound among the given structures is $\text{C}_5\text{H}_5\text{N}$ (Pyridine).

Identify the major product (G) in the following reaction (Bromination with \( Br_2/FeBr_3 \)). 


MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
