Step 1: Understanding the Concept:
This question asks for a comparison between the square of \(\pi\) and the number 10. We are given approximate values for \(\pi\) and \(\sqrt{10}\) to help with the comparison.
Step 2: Key Formula or Approach:
The most direct way to compare \(\pi^2\) and 10 is to compare \(\pi\) and \(\sqrt{10}\). If \(a\) and \(b\) are positive numbers, then \(a<b\) is equivalent to \(a^2<b^2\).
Step 3: Detailed Explanation:
We are given the approximations \(\pi \approx 3.14\) and \(\sqrt{10} \approx 3.16\).
Based on these values, we can see that \(\pi\) is less than \(\sqrt{10}\).
\[ 3.14<3.16 \]
\[ \pi<\sqrt{10} \]
Since both \(\pi\) and \(\sqrt{10}\) are positive numbers, we can square both sides of the inequality without changing its direction:
\[ \pi^2<(\sqrt{10})^2 \]
\[ \pi^2<10 \]
This shows that the quantity in Column A is less than the quantity in Column B.
Alternatively, we could square the given approximation for \(\pi\):
\[ \pi^2 \approx (3.14)^2 = 3.14 \times 3.14 = 9.8596 \]
Since 9.8596 is less than 10, the quantity in Column A is smaller.
Step 4: Final Answer:
Both methods show that \(\pi^2\) is less than 10. Therefore, the quantity in Column B is greater.