Step 1: Understanding the Question:
This question belongs to the topic of
3D Spatial Reasoning and Orthographic Projections.
We are given three orthographic views of a 3D stack of cubes: Top View, Front View, and Side View.
The goal is to determine the absolute minimum number of sugar cubes required to construct a stable 3D stack that satisfies all three views simultaneously.
Step 2: Key Formula or Approach:
We represent the stack as a 2D grid matching the Top View. Let the height of the cube stack at grid position \((i, j)\) be denoted by \(h_{i,j}\).
• The Top View shows a complete \(4 \times 4\) grid filled with squares, which means there must be at least one cube at every coordinate: \(h_{i,j} \ge 1\) for all \(1 \le i, j \le 4\).
• The Front View gives the maximum height of each column \(j\): \(\max_i h_{i,j}\). From left to right, these column maximums are: 4, 4, 3, 2.
• The Side View gives the maximum height of each row \(i\): \(\max_j h_{i,j}\). From back to front, these row maximums are: 4, 3, 2, 1.
• To minimize the total number of cubes, we must minimize the sum \(\sum_{i,j} h_{i,j}\) by overlapping the maximum height demands of rows and columns as much as possible.
Step 3: Detailed Explanation:
• Let us initialize all 16 cells in the \(4 \times 4\) grid with a height of 1 to satisfy the Top View requirement. This accounts for a base count of 16 cubes.
• Let us look at the row maximum requirements:
- Row 4 (front-most) has a maximum height of 1. Since all cells in this row are initialized to 1, this requirement is already satisfied.
- Row 3 has a maximum height of 2.
- Row 2 has a maximum height of 3.
- Row 1 (back-most) has a maximum height of 4.
• Let us look at the column maximum requirements:
- Column 1 has a maximum of 4.
- Column 2 has a maximum of 4.
- Column 3 has a maximum of 3.
- Column 4 has a maximum of 2.
• We can overlap these requirements strategically:
- Place a height of 4 at position \((1, 1)\). This satisfies Row 1 max (4) and Column 1 max (4) simultaneously.
- Place a height of 4 at position \((1, 2)\). This satisfies Row 1 max (4) and Column 2 max (4).
- Place a height of 3 at position \((2, 3)\). This satisfies Row 2 max (3) and Column 3 max (3) simultaneously.
- Place a height of 2 at position \((3, 4)\). This satisfies Row 3 max (2) and Column 4 max (2) simultaneously.
• All other cells can remain at their minimum height of 1. Let us write down the optimized height grid:
Row 1: [4, 4, 1, 1] (Max = 4)
Row 2: [1, 1, 3, 1] (Max = 3)
Row 3: [1, 1, 1, 2] (Max = 2)
Row 4: [1, 1, 1, 1] (Max = 1)
• Let us verify the column maximums for this grid:
Col 1: \(\max(4, 1, 1, 1) = 4\) (Satisfied)
Col 2: \(\max(4, 1, 1, 1) = 4\) (Satisfied)
Col 3: \(\max(1, 3, 1, 1) = 3\) (Satisfied)
Col 4: \(\max(1, 1, 2, 1) = 2\) (Satisfied)
• Let us sum the heights of all 16 cells in this optimized configuration:
\[ \text{Total Cubes} = (4 + 4 + 1 + 1) + (1 + 1 + 3 + 1) + (1 + 1 + 1 + 2) + (1 + 1 + 1 + 1) \]
\[ \text{Total Cubes} = 10 + 6 + 5 + 4 = 25 \]
Step 4: Final Answer:
The minimum number of cubes required to produce this stack is 25, which corresponds to option (A).