Step 1: Understanding the Question:
We need to find the ratio of air quantities flowing through three parallel airways that are identical except for their lengths.
Step 2: Key Formula or Approach:
1. For airways in
parallel, the pressure drop (H) across each branch is the same.
2. The fundamental ventilation equation is \( H = R Q^2 \), where H is pressure, R is resistance, and Q is quantity.
3. From the previous question, we know that for these airways, resistance is directly proportional to length (\( R \propto L \)).
Step 3: Detailed Explanation:
Since the pressure drop is the same for all three roadways:
\[ H = R_A Q_A^2 = R_B Q_B^2 = R_C Q_C^2 \]
This means that \( Q^2 \) is inversely proportional to R:
\[ Q^2 \propto \frac{1}{R} \]
Taking the square root, we find that the quantity Q is inversely proportional to the square root of the resistance:
\[ Q \propto \frac{1}{\sqrt{R}} \]
Since resistance is proportional to length (\( R \propto L \)), we can say:
\[ Q \propto \frac{1}{\sqrt{L}} \]
Now we can write the ratio of the quantities:
\[ Q_A : Q_B : Q_C = \frac{1}{\sqrt{L_A}} : \frac{1}{\sqrt{L_B}} : \frac{1}{\sqrt{L_C}} \]
Substitute the given lengths \( L_A=100 \), \( L_B=200 \), \( L_C=300 \):
\[ Q_A : Q_B : Q_C = \frac{1}{\sqrt{100}} : \frac{1}{\sqrt{200}} : \frac{1}{\sqrt{300}} \]
\[ Q_A : Q_B : Q_C = \frac{1}{\sqrt{100 \times 1}} : \frac{1}{\sqrt{100 \times 2}} : \frac{1}{\sqrt{100 \times 3}} \]
\[ Q_A : Q_B : Q_C = \frac{1}{10\sqrt{1}} : \frac{1}{10\sqrt{2}} : \frac{1}{10\sqrt{3}} \]
To simplify the ratio, we can multiply all parts by 10:
\[ Q_A : Q_B : Q_C = 1 : \frac{1}{\sqrt{2}} : \frac{1}{\sqrt{3}} \]
Step 4: Final Answer:
The ratio of the quantities is 1 : \( 1/\sqrt{2} \) : \( 1/\sqrt{3} \).
This corresponds to option (D).