Three frictionless pulleys with rope attachment are in a static equilibrium as shown in the figure. The mass \( m_1 \) and \( m_2 \), in kg, respectively are:

In this question, the system is in static equilibrium, which means the net forces acting on the system must sum to zero.
Step 1: Analyze the forces on the system.
The weight of the mass \( 100 \, {kg} \) creates a force acting downwards. For the system to be in equilibrium, the forces acting on the pulleys must balance.
Let the tension in the rope be denoted as \( T \).
Step 2: Set up the equilibrium equations.
For the pulley system, the forces must satisfy the condition for static equilibrium. This leads to the following relationships between the masses: The tension force in the rope is the same at all points (since the pulleys are frictionless).
The total force on the mass \( m_1 \) and \( m_2 \) must balance the downward force from the \( 100 \, {kg} \) mass.
Using these relationships, we find that:
\( m_1 = 50 \, {kg} \)
\( m_2 = 100 \, {kg} \)
Conclusion: The correct answer is (A) 50, 100.
| Day | Convergence reading (mm) |
| 0 | 0 |
| 5 | 4.7 |
| 10 | 11.3 |
| 16 | 19.6 |
| 22 | 28.8 |
| 30 | 34.8 |
| Line | Length (m) | Bearing |
| AB | 100 | 90° |
| BC | 120 | 150° |
The length, in m and bearing of line CA, in degree, respectively, are
