Concept:
- Frame count and frame rate are linked by $\text{duration} = \dfrac{\text{frames}}{\text{fps}}$, so two setups give the SAME duration exactly when $\dfrac{\text{frames}_1}{\text{fps}_1} = \dfrac{\text{frames}_2}{\text{fps}_2}$.
- This ratio check can be done by cross-multiplication, without ever converting to seconds -- useful for checking several statements quickly against one reference setup.
- Frame rate and loop duration are inversely related when the frame count is fixed: raising fps always shortens the loop, lowering fps always lengthens it.
Step 1: Set up the reference ratio for the original animation.
24 frames at 12 fps gives the pair $(24, 12)$.
Step 2: Test Statement 1 by cross-multiplication instead of dividing.
Statement 1 claims the loop takes 3 seconds, which is the same as claiming the pair $(3, 1)$ matches $(24, 12)$ in frames-per-second terms, i.e. 3 seconds at 1 frame per second is not what is being compared -- instead check $24 \times 1$ against $3 \times 12$: $24 \ne 36$, so the ratios do not match and the statement is false.
Step 3: Test Statement 3 using the inverse relationship, with no division at all.
The frame count stays fixed at 24. Since duration $=\dfrac{24}{\text{fps}}$, duration grows as fps falls. Dropping from 12 fps to 8 fps is a fall in fps, so the loop must take longer, not less time -- the animation plays slower, never faster. Statement 3 is false.
Step 4: Test Statement 4 by cross-multiplication against the same reference pair.
The claim is that $(6, 3)$ gives the same duration as $(24, 12)$. Cross-multiply: $6 \times 12 = 72$ and $24 \times 3 = 72$. Both sides match, so $(6, 3)$ does reproduce the same loop duration as the original, and Statement 4 is true.
Step 5: Check Statement 2 using time-per-frame instead of frames-per-dot.
Time for one frame $= \dfrac{1}{12}$ second. With the dots dividing the 24-frame loop evenly, the white phase for each dot lasts 4 frames, which is $4 \times \dfrac{1}{12} = \dfrac{1}{3}$ second -- a fixed, sensible fraction of the 2 second loop, consistent with an even split across the loop. Statement 2 is true.
Final Answer: Statements 2 and 4 are true; Statements 1 and 3 are false.