Step 1: Formula of thermal diffusivity.
\[
\alpha = \frac{k}{\rho c}
\]
where:
- \( \alpha \) = thermal diffusivity
- \( k \) = thermal conductivity
- \( \rho \) = density
- \( c \) = specific heat capacity
Step 2: Check each statement.
- (A) Inverse relation with \(k\)? No, it is directly proportional. ✗
- (B) Higher \(c\) → denominator increases → diffusivity decreases. Not increases. ✗
- (C) Low diffusivity = slower heat transfer = higher dampening of temperature waves. ✓
- (D) Higher density → denominator increases → diffusivity decreases → inverse relation. ✓
Final Answer: \[ \boxed{(C) \; \text{and} \; (D)} \]
Using the following values of thermal conductance, surface conductance, and thermal resistance, the U value across the given wall cross-section is \(\underline{\hspace{1cm}}\) W/m\(^2\)°C (round off to 2 decimal places). 
