Thermal decomposition of a Mn compound (X) at 513 K results in compound Y, MnO2 and gaseous product. MnO2 reacts with NaCl and concentrated H2O4 to give a pungent gas Z. X, Y and Z, respectively, are :
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- KMnO4, K2MnO4 and Cl2
- K2MnO4, KMnO4 and SO2
- K3MnO4, K2MnO4 and Cl2
- K2MnO4, KMnO4 and Cl2
The Correct Option is A
Solution and Explanation
MnO2 with NaCl and conc. H2SO4 (printed as H2O4): MnO2 + 4NaCl + 4H2SO4 → MnCl2 + 4NaHSO4 + 2H2O + Cl2. The pungent gas Z = Cl2.
So X, Y, Z = KMnO4, K2MnO4, Cl2.
Answer: (1) KMnO4, K2MnO4 and Cl2
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