Question:

There are 23 buses available between Dinu's house and his school. How many ways are possible for Dinu to go from his house to school and return using different buses?

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Always subtract the "already used" option from the total if the question specifies that items or routes cannot be repeated (different buses, no repetition, etc.).
Updated On: Apr 20, 2026
  • 529
  • 506
  • 463
  • 484
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This involves two sequential events where the second event is dependent on the choice of the first event because a "different" bus must be used for the return journey.

Step 2: Key Formula or Approach:

Total ways = (Ways to go) $\times$ (Ways to return)

Step 3: Detailed Explanation:

1. Going to school: There are 23 buses available. So, Dinu has 23 ways to go to school. 2. Returning home: He must use a different bus than the one he took to school. 3. Therefore, available buses for return = $23 - 1 = 22$ buses. 4. Total ways = $23 \times 22$. \[ 23 \times 22 = 23 \times (20 + 2) = 460 + 46 = 506. \]

Step 4: Final Answer:

There are 506 possible ways for Dinu to complete his journey.
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