Question

The zeroes of the polynomial \( x^2 - 11 \) are:

• A. \( 11, -11 \)
• B. \( 11, -\sqrt{11} \)
• C. \( \sqrt{11}, -\sqrt{11} \)
• D. \( \sqrt{11}, -11 \)

Hint:

To find the zeroes of a quadratic polynomial \( ax^2 + bx + c \), use the formula \( x = \pm \sqrt{-c/a} \) if \( b = 0 \).

Answer 1

The Correct Option is C

Step 1: To find the zeroes of the polynomial \( x^2 - 11 \), we set the equation equal to zero: \[ x^2 - 11 = 0 \] Step 2: Solving for \( x \), we get: \[ x^2 = 11 \] Step 3: Taking the square root of both sides, we get: \[ x = \pm \sqrt{11} \] Thus, the zeroes of the polynomial are \( \sqrt{11} \) and \( -\sqrt{11} \).