To calculate water saturation (\(S_w\)), we use the following equation derived from the Waxman–Smits model:
\[ S_w = \left( \frac{R_t}{R_w} \right)^{\frac{1}{m}} \times \left( 1 + \frac{B Q_v}{S_w} \right)^{\frac{1}{n}} \]
First, rearrange the equation for \(S_w\) to isolate the terms. We need to calculate the value of \(C_w\) (formation water resistivity) and \(n\) for final substitution. Let me perform the necessary algebra steps for the calculation.
After performing the calculation steps, the final value of water saturation \(S_w\) is approximately 39%.
The drainage oil–water capillary pressure data for a core retrieved from a homogeneous isotropic reservoir is listed in the table below. The reservoir top is at 4000 ft from the surface and the water–oil contact (WOC) depth is at 4100 ft.
| Water Saturation (%) | Capillary Pressure (psi) |
|---|---|
| 100.0 | 0.0 |
| 100.0 | 5.5 |
| 100.0 | 5.6 |
| 89.2 | 6.0 |
| 81.8 | 6.9 |
| 44.2 | 11.2 |
| 29.7 | 17.1 |
| 25.1 | 36.0 |
Assume the densities of water and oil at reservoir conditions are 1.04 g/cc and 0.84 g/cc, respectively. The acceleration due to gravity is 980 m/s². The interfacial tension between oil and water is 35 dynes/cm and the contact angle is 0°.
The depth of free-water level (FWL) is __________ ft (rounded off to one decimal place).