
At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)
Consider the normal incidence of a plane electromagnetic wave with electric field given by \[ \vec{E} = E_0 \exp{[i(k_1 z - \omega t)]} \hat{x} \] over an interface at \( z = 0 \) separating two media [wave velocities \( v_1 \) and \( v_2 \) (with \( v_2>v_1 \)) and wave vectors \( k_1 \) and \( k_2 \), respectively], as shown in the figure. The magnetic field vector of the reflected wave is 
