The volume strength of 8.9 M \(\mathrm{H_2O_2}\) solution calculated at 273 K and 1 atm is ______. (R = 0.0821 L atm \(\mathrm{K^{-1}\,mol^{-1}}\)) (rounded off ot the nearest integer)
Show Hint
Correct Answer: 100
Solution and Explanation
1 L of 8.9 M solution contains 8.9 mol \(\mathrm{H_2O_2}\), which gives 8.9/2 = 4.45 mol \(\mathrm{O_2}\).
Volume at 273 K, 1 atm: \(V = nRT/P = 4.45 \times 0.0821 \times 273 / 1\).
0.0821 \(\times\) 273 = 22.41 L/mol, so V = 4.45 \(\times\) 22.41 = 99.74 L.
Volume strength \(\approx\) 99.74, i.e. 100 (nearest integer).
Answer: 100
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main hydrogen peroxide Questions
- ' $25$ volume' hydrogen peroxide means
- The products obtained from a reaction of hydrogen peroxide and acidified potassium permanganate are
- The correct statements about \(\mathrm{H_2O_2}\) are :
(A) used in the treatment of effluents.
(B) used as both oxidising and reducing agents.
(C) the two hydroxyl groups lie in the same plane.
(D) miscible with water.
Choose the correct answer from the options given below : - Given below are two statements :
Statement I : H\(_2\)O\(_2\) can act as both oxidising and reducing agent in basic medium.
Statement II : In the hydrogen economy, the energy is transmitted in the form of dihydrogen.
In the light of the above statements, choose the correct answer from the options given below : - Given below are two statements : One is labelled as Assertion A and other is labelled as Reason R.
Assertion A : The dihedral angles in \(\mathrm{H_2O_2}\) in gaseous phase is \(90.2^\circ\) and in solid phase is \(111.5^\circ\).
Reason R : The change in dihedral angle in solid and gaseous phase is due to the difference in the intermolecular forces.
Choose the most appropriate answer from the options given below for A and R.
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,