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the vertices of the hyperbola are at 5 3 and 5 1 a
Question:
The vertices of the hyperbola are at (-5,-3) and (-5,-1) and the extremities of the conjugate axis are at (-7,-2) and (-3,-2), then the equation of the hyperbola is
BCECE - 2017
BCECE
Updated On:
May 21, 2025
\(\frac{(y-2)^2}{1}-\frac{(x-5)^2}{4}=1\)
\(\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1\)
\(\frac{(x+5)^2}{4}-\frac{(y+2)^2}{1}=1\)
\(\frac{(x-5)^2}{4}-\frac{(y-2)^2}{1}=1\)
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The Correct Option is
B
Solution and Explanation
The correct option is (B) :
\(\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1\)
.
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