The value of \( \lim_{x \to \infty} \dfrac{x \ln(x)}{1 + x^2} \) is:
We are asked to evaluate the limit: \[ \lim_{x \to \infty} \frac{x \ln(x)}{1 + x^2}. \] As \( x \to \infty \), the denominator grows much faster than the numerator because \( x^2 \) dominates \( \ln(x) \). Therefore, the limit of this expression as \( x \to \infty \) is 0.
Final Answer: \[ \boxed{0}. \]