We are asked to evaluate the limit:
\[
\lim_{x \to 0} \left[ \frac{1}{x} \ln(1+x) \right]
\]
Step 1: Apply L'Hopital's Rule.
The given expression is of the indeterminate form \( \frac{0}{0} \) when \( x \to 0 \), so we can apply L'Hopital's Rule. Differentiating the numerator and denominator separately:
Numerator:
\[
\frac{d}{dx} \left( \ln(1+x) \right) = \frac{1}{1+x}
\]
Denominator:
\[
\frac{d}{dx} (x) = 1
\]
Step 2: Evaluate the limit.
Using L'Hopital's Rule, we get the limit:
\[
\lim_{x \to 0} \frac{\frac{1}{1+x}}{1} = \lim_{x \to 0} \frac{1}{1+x} = 1
\]
Thus, the value of the limit is 1.