Step 1: Observe the nature of the function.
The integrand is
\[
f(x) = \sin^{7}x
\]
We know that the sine function is an odd function.
An odd function satisfies the property
\[
f(-x) = -f(x)
\]
Step 2: Check whether the integrand is odd.
Since $\sin x$ is odd,
\[
\sin(-x) = -\sin x
\]
Thus,
\[
\sin^{7}(-x) = (-\sin x)^7
\]
\[
= -\sin^{7}x
\]
Hence $\sin^{7}x$ is also an odd function.
Step 3: Use the property of definite integrals of odd functions.
If a function is odd and the limits of integration are symmetric about zero,
\[
\int_{-a}^{a} f(x)\,dx = 0
\]
Here the limits are
\[
-\frac{\pi}{2} \quad \text{to} \quad \frac{\pi}{2}
\]
which are symmetric about zero.
Step 4: Apply the property.
Therefore,
\[
\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \sin^{7}x \, dx = 0
\]
Step 5: Conclusion.
Thus the value of the definite integral is zero.
Final Answer: $\boxed{0}$