The correct answer is: 6
\(l=∫_3^b \frac{1}{(x^2-1)(x^2-4)}dx=\frac{1}{3}(\frac{1}{x^2-4}-\frac{1}{x^2-1})dx\)
\(=ln((\frac{b-2}{b+2})\frac{(b+1)^2}{b-1}^2)-(In\,\frac{4}{5})\)
After simplification ,
\(\frac{49}{40}=\frac{(b-2)}{(b+2)}\frac{(b+1)^2}{(b-1)^2}.\frac{5}{4}\)
⇒ b = 6
The area enclosed by the closed curve $C$ given by the differential equation $\frac{d y}{d x}+\frac{x+a}{y-2}=0, y(1)=0$ is $4 \pi$.
Let $P$ and $Q$ be the points of intersection of the curve $C$ and the $y$-axis If normals at $P$ and $Q$ on the curve $C$ intersect $x$-axis at points $R$ and $S$ respectively, then the length of the line segment $R S$ is


The number of formulas used to decompose the given improper rational functions is given below. By using the given expressions, we can quickly write the integrand as a sum of proper rational functions.

For examples,
