The upper limit of the scale of dial reading for a rotational oilfield viscometer is 300 degrees. At a rotational speed of 100 RPM, the highest possible effective (apparent) viscosity that can be measured on this viscometer (in cP) is ________ (rounded off to one decimal place). [Given: 1 degree dial reading = 5.11 dynes/cm2, and 1 RPM = 1.703 s^-1]
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Convert the maximum dial reading to shear stress and the RPM to shear rate, then divide the two to get the apparent viscosity.
Step 1: List the given data: Maximum dial reading = 300 degrees Rotational speed N = 100 RPM 1 degree dial reading = 5.11 dynes/cm2 1 RPM = 1.703 s^-1 Step 2: Convert the maximum dial reading into shear stress: Shear stress tau = 300 x 5.11 tau = 1533 dynes/cm2 Step 3: Convert this shear stress into SI units (Pa), using 1 dyne/cm2 = 0.1 Pa: tau = 1533 x 0.1 tau = 153.3 Pa Step 4: Convert the rotational speed into shear rate: Shear rate = 100 x 1.703 Shear rate = 170.3 s^-1 Step 5: Compute the effective (apparent) Newtonian viscosity from the ratio of shear stress to shear rate: \[ \mu_a = \frac{\tau}{\dot{\gamma}} = \frac{153.3}{170.3} \] mu_a = 0.90018 Pa.s Step 6: Convert this viscosity from Pa.s into centipoise, using 1 Pa.s = 1000 cP: mu_a = 0.90018 x 1000 mu_a = 900.2 cP Final Answer: \[ \boxed{\mu_a = 900.2 \text{ cP}} \]