The transfer function is in the form: \[ \frac{10}{s^2 + 2\zeta \omega_n s + \omega_n^2} \] Comparing coefficients, $\omega_n^2 = 10$ and $2\zeta \omega_n = 3$.
Thus, $\omega_n = \sqrt{10}$ and $\zeta = \frac{3}{2\sqrt{10}} \approx 0.5$.
Given an open-loop transfer function \(GH = \frac{100}{s}(s+100)\) for a unity feedback system with a unit step input \(r(t)=u(t)\), determine the rise time \(t_r\).
Consider a linear time-invariant system represented by the state-space equation: \[ \dot{x} = \begin{bmatrix} a & b -a & 0 \end{bmatrix} x + \begin{bmatrix} 1 0 \end{bmatrix} u \] The closed-loop poles of the system are located at \(-2 \pm j3\). The value of the parameter \(b\) is: