The total surface area (TSA) of a hemisphere is:
\[
\text{TSA} = 3\pi r^2
\]
Given the diameter \( d = 14 \) cm, so radius:
\[
r = \frac{14}{2} = 7 \text{ cm}
\]
\[
\text{TSA} = 3\pi (7)^2 = 3\pi (49) = 147\pi
\]
Since the total surface area includes the circular base:
\[
\text{TSA} = 147\pi + 49\pi = 198\pi \text{ cm}^2
\]