The total number of unpaired electrons present in \(\mathrm{[Co(NH_3)_6]Cl_2}\) and \(\mathrm{[Co(NH_3)_6]Cl_3}\) is :
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Correct Answer: 3
Solution and Explanation
\(\mathrm{[Co(NH_3)_6]Cl_3}\): Co is +3, 3d6 with strong-field \(\mathrm{NH_3}\) giving the low-spin \(t_{2g}^6 e_g^0\): 0 unpaired electrons.
Total unpaired electrons = 3 + 0 = 3.
Answer: 3
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