The total number of ‘Sigma’ and Pi bonds in 2 formylhex-4-enoic acid is ____.
Correct Answer: 22
Solution and Explanation
Bond Analysis of 2-formylhex-4-enoic acid
Compound Structure:
The compound 2-formylhex-4-enoic acid has the molecular structure represented as:
\(H–O–C(=O)–CH(CHO)–CH_2–CH=CH–CH_3\)
Where the numbering of carbon atoms is as follows: \(C_1\) to \(C_6\).
Bond Analysis:
Each single bond is a \(\sigma\) (sigma) bond, and each double bond consists of one \(\sigma\) and one \(\pi\) (pi) bond.
- There are 19 sigma (\(\sigma\)) bonds in total.
- There are 3 pi (\(\pi\)) bonds in total.
Detailed Explanation:
1. The molecule contains both a –COOH (carboxylic acid) group and a –CHO (formyl) group.
2. The C=O bonds in both groups contribute two \(\pi\) bonds.
3. The C=C double bond at position 4–5 adds one more \(\pi\) bond.
4. Adding all sigma and pi bonds, we get:
\[\sigma\text{-bonds} = 19, \quad \pi\text{-bonds} = 3\]Final Answer:
\[\boxed{\sigma = 19, \quad \pi = 3}\]Top JEE Main Chemistry Questions
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