The total number of isomers for a square planar complex [M(F)(Cl)(SCN)(NO\(_2\))] is
Show Hint
- 16
- 8
- 12
- 4
The Correct Option is C
Solution and Explanation
SCN\(^-\) is ambidentate (binds through S or N): 2 linkage modes. NO\(_2^-\) is ambidentate (binds through N or O): 2 linkage modes.
Total isomers = 3 \(\times\) 2 \(\times\) 2 = 12.
Answer: (3) 12
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