Question

The total number of hydrogen atoms in product A and product B is ______.

Answer 1

Correct Answer: 10

Reaction Breakdown: 

The given reaction involves the following steps:

1. The compound \( \text{CH}_3\text{CH}_2\text{Br} \) (ethyl bromide) reacts with sodium hydroxide (\( \text{NaOH} \)).
2. In the first reaction, ethanol \( \text{C}_2\text{H}_5\text{OH} \) is formed, leading to the creation of an alkene, \( \text{CH}_2 = \text{CH}_2 \), which is ethene.
3. In the second step, water (\( \text{H}_2\text{O} \)) adds to the double bond in ethene, resulting in ethanol \( \text{CH}_3\text{CH}_2\text{OH} \).

Total Hydrogen Atoms in Reactants and Products:

Let's count the number of hydrogen atoms in the reactants (A) and products (B):

• Reactant A: \( \text{CH}_3\text{CH}_2\text{Br} \) (ethyl bromide): - \( \text{CH}_3 \) has 3 hydrogen atoms. - \( \text{CH}_2 \) has 2 hydrogen atoms. - Total = \( 3 + 2 = 5 \) hydrogen atoms.
• Reactant B: \( \text{NaOH} \) (sodium hydroxide) does not contribute any hydrogen atoms.
• Product 1: \( \text{CH}_2 = \text{CH}_2 \) (ethene): - Each \( \text{CH}_2 \) group contributes 2 hydrogen atoms. - Total = \( 2 + 2 = 4 \) hydrogen atoms.
• Product 2: \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol): - \( \text{CH}_3 \) has 3 hydrogen atoms. - \( \text{CH}_2 \) has 2 hydrogen atoms. - The hydroxyl group (\( \text{OH} \)) contributes 1 hydrogen atom. - Total = \( 3 + 2 + 1 = 6 \) hydrogen atoms.

Total Number of Hydrogen Atoms: Adding the hydrogen atoms from both reactants and products gives:

Total number of hydrogen atoms in A and B is \( 5 \) (from \( \text{CH}_3\text{CH}_2\text{Br} \)) \( + 6 \) (from \( \text{CH}_3\text{CH}_2\text{OH} \)) = 10 hydrogen atoms.

Answer 2

Total number of hydrogen atoms in Product A and Product B is 10.