The total number of hydrogen atoms in product A and product B is ______.
The total number of hydrogen atoms in product A and product B is ______.
Correct Answer: 10
Approach Solution - 1
Reaction Breakdown:
The given reaction involves the following steps:
- The compound \( \text{CH}_3\text{CH}_2\text{Br} \) (ethyl bromide) reacts with sodium hydroxide (\( \text{NaOH} \)).
- In the first reaction, ethanol \( \text{C}_2\text{H}_5\text{OH} \) is formed, leading to the creation of an alkene, \( \text{CH}_2 = \text{CH}_2 \), which is ethene.
- In the second step, water (\( \text{H}_2\text{O} \)) adds to the double bond in ethene, resulting in ethanol \( \text{CH}_3\text{CH}_2\text{OH} \).
Total Hydrogen Atoms in Reactants and Products:
Let's count the number of hydrogen atoms in the reactants (A) and products (B):
- Reactant A: \( \text{CH}_3\text{CH}_2\text{Br} \) (ethyl bromide): - \( \text{CH}_3 \) has 3 hydrogen atoms. - \( \text{CH}_2 \) has 2 hydrogen atoms. - Total = \( 3 + 2 = 5 \) hydrogen atoms.
- Reactant B: \( \text{NaOH} \) (sodium hydroxide) does not contribute any hydrogen atoms.
- Product 1: \( \text{CH}_2 = \text{CH}_2 \) (ethene): - Each \( \text{CH}_2 \) group contributes 2 hydrogen atoms. - Total = \( 2 + 2 = 4 \) hydrogen atoms.
- Product 2: \( \text{CH}_3\text{CH}_2\text{OH} \) (ethanol): - \( \text{CH}_3 \) has 3 hydrogen atoms. - \( \text{CH}_2 \) has 2 hydrogen atoms. - The hydroxyl group (\( \text{OH} \)) contributes 1 hydrogen atom. - Total = \( 3 + 2 + 1 = 6 \) hydrogen atoms.
Total Number of Hydrogen Atoms: Adding the hydrogen atoms from both reactants and products gives:
Total number of hydrogen atoms in A and B is \( 5 \) (from \( \text{CH}_3\text{CH}_2\text{Br} \)) \( + 6 \) (from \( \text{CH}_3\text{CH}_2\text{OH} \)) = 10 hydrogen atoms.
Approach Solution -2
Total number of hydrogen atoms in Product A and Product B is 10.
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