Question

The total number of genetically different types of gametes that will be produced by a heterozygous plant carrying the genotypes AABbCc is ...............

Hint:

The total number of genetically different gametes produced is the product of the number of alleles at each heterozygous locus.

Answer 1

Correct Answer: 4

Step 1: Identifying the number of heterozygous loci. 
The plant's genotype is AABbCc. In this case: - AA is homozygous, so it can only produce one type of allele (A). - Bb is heterozygous, so it can produce two types of alleles (B and b). - Cc is heterozygous, so it can produce two types of alleles (C and c).

Step 2: Calculating the number of genetically different gametes. 
The number of different types of gametes produced depends on the number of heterozygous loci, because each heterozygous locus can produce two types of alleles. 

- For gene A (AA): Only one type of allele, A, is possible. 

- For gene B (Bb): Two types of alleles, B and b, are possible. 

- For gene C (Cc): Two types of alleles, C and c, are possible. 

The total number of genetically different gametes can be calculated by multiplying the number of possibilities for each locus: \[ \text{Total number of gametes} = 1 \times 2 \times 2 = 4 \]

Step 3: Conclusion. 
Thus, the total number of genetically different types of gametes produced is 4. Therefore, the correct answer is 4.