The third ionization enthalpy is minimum for :
Show Hint
- Ni
- Co
- Mn
- Fe
The Correct Option is D
Solution and Explanation
Mn\(^{2+}\): \(3d^5\) (half-filled, very stable), so removing a further electron is hard.
Fe\(^{2+}\): \(3d^6\to\) Fe\(^{3+}\): \(3d^5\), the loss gives a stable half-filled configuration, so it is easiest.
Co\(^{2+}\) (\(3d^7\)) and Ni\(^{2+}\) (\(3d^8\)) do not gain such stability and have higher values.
Approximate values (kJ/mol): Mn 3248, Fe 2957, Co 3232, Ni 3395. Fe is minimum.
Answer: (4) Fe
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