The problem requires us to convert a temperature difference from Celsius to Fahrenheit. The conversion formula between Celsius and Fahrenheit is:
F = (C × 9/5) + 32
For temperature differences, the constant 32 does not affect the result, so we only need:
ΔF = ΔC × 9/5
Given that the temperature difference ΔC is 1°C:
ΔF = 1 × 9/5 = 9/5 = 1.8°F
Thus, the temperature difference of 1°C corresponds to a difference of 1.8°F on the Fahrenheit scale. The correct answer is 1.8°F.

Potential energy (V) versus distance (x) is given by the graph. Rank various regions as per the magnitudes of the force (F) acting on a particle from high to low. 
In the system shown below, $x(t)=\sin(t)u(t)$. In steady-state, the response $y(t)$ will be 
The time constant of the network shown in the figure is 
The parallel RLC circuit shown in the figure is in resonance. In this circuit, 