The temperature at which oxygen molecules have the same root mean square speed as helium atoms have at 300 K is : (Atomic masses : He = 4 u, O = 16 u)
Show Hint
- \(600\ \mathrm{K}\)
- \(2400\ \mathrm{K}\)
- \(1200\ \mathrm{K}\)
- \(300\ \mathrm{K}\)
The Correct Option is B
Solution and Explanation
Equal speeds: \(\dfrac{T_{O_2}}{M_{O_2}}=\dfrac{T_{He}}{M_{He}}\)
\(M_{O_2}=32\) g/mol, \(M_{He}=4\) g/mol
\(T_{O_2}=300\times\dfrac{32}{4}=2400\ \mathrm{K}\)
Answer: (2) 2400 K
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